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-x^2+47x+30=0
We add all the numbers together, and all the variables
-1x^2+47x+30=0
a = -1; b = 47; c = +30;
Δ = b2-4ac
Δ = 472-4·(-1)·30
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(47)-\sqrt{2329}}{2*-1}=\frac{-47-\sqrt{2329}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(47)+\sqrt{2329}}{2*-1}=\frac{-47+\sqrt{2329}}{-2} $
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